MF_TmulV MD_TmulV ME_TmulV
Functionmultiply the transpose of a matrix by a column vector
Syntax C/C++#include <MFstd.h>
void MF_TmulV( fVector Y, fMatrix MA, fVector X, ui htA, ui lenA );
C++ MatObj#include <OptiVec.h>
void vector<T>::TmulV( const matrix<T>& MA, const vector<T>& X  );
Pascal/Delphiuses MFstd;
procedure MF_TmulV( Y:fVector; MA:fMatrix; X:fVector; htA, lenA:UIntSize );
CUDA function C/C++#include <cudaMFstd.h>
int cudaMF_TmulV( fVector d_Y, fMatrix d_MA, fVector d_X, ui htA, ui lenA );
void MFcu_TmulV( fVector h_Y, fMatrix h_MA, fVector h_X, ui htA, ui lenA );
CUDA function Pascal/Delphiuses MFstd;
function cudaMF_TmulV( d_Y:fVector; d_MA:fMatrix; d_X:fVector; htA, lenA:UIntSize ): IntBool;
procedure MFcu_TmulV( h_Y:fVector; h_MA:fMatrix; h_X:fVector; htA, lenA:UIntSize );
DescriptionY = MAT * X
The dimensions htA and lenA refer to the original (rather than the intermediate transposed) matrix MA; the dimensions of X and Y are implicitly given by the matrix dimensions: sizX = htA, sizY = lenA.
See alsoMF_mulV,   VF_mulM,   chapter 9

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